# KINEMATYKA WZORY PDF

Wzory kinematyczne ruchu obrotowego. O nas. Transkrypcja. David explains the. mechanika dział fizyki zajmujący się ruchem, równowagą i oddziaływaniem ciał. mechanika klasyczna opiera się na trzech zasadach dynamiki newtona i bada. w opisie kinematyki oraz dynamiki ukła- dów korbowo-tłokowych . KINEMATYKA UKŁADU KORBOWO- jest od kąta α i dane jest wzorem (3), (5). The shift of. Author: Dimuro Gokus Country: Japan Language: English (Spanish) Genre: Career Published (Last): 11 March 2018 Pages: 42 PDF File Size: 16.23 Mb ePub File Size: 19.97 Mb ISBN: 849-2-61913-196-4 Downloads: 80550 Price: Free* [*Free Regsitration Required] Uploader: Disida  Now this second part, part b, says what was the angular velocity after rotating for five revolutions? So kinematyla find the speed we could just say that that’s equal to four meters, since you wanna know the speed of a point out here that’s four meters wzoty the axis, and we multiply by the angular velocity, which initially was 40 radians per second.

So there’s no such thing as angular time or linear time.

That’s why I left this blank over here, but we could write radians if we wanted to. Let’s carry our kinematic formulas kinematyoa us.

To me, this first one’s the simplest. The way I figure out what kinematic formula to use is that I just ask which variable’s left out of all these? There’s not even a ratio or anything, so let’s use this. You’ve gotta make sure you compare apples to apples. In other words, if something’s speeding up, you have to make sure that your angular acceleration has the same sign as your angular velocity, and your angular velocity’ll have the same sign as your angular displacement.

And then it’s gonna be plus two times alpha. And time is just time. And that’s the time. We wanna know the time that it took.

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So let me get rid of all this and let’s tackle this problem. But remember this only works, these equations only work if the acceleration is constant. Sometimes people write the radian, sometimes they leave it blank. How do we tackle these problems? We replace all of our accelerations with angular accelerations. So now we just solve this algebraically for time.

## Wzory kinematyczne ruchu obrotowego

These are the rotational kinematic formulas. Whoa, that’d be a more difficult problem, we’re gonna rotate this. And that’ll end up giving us 20 pi, and technically that is 20 pi radians divided by 30 radians per second squared and then you have to take the square root, because it’s t squared. As far as we know, there’s only one time and that’s t and that works in either equation.

This is in units for revolutions. Well this thing slowed down to a stop. Because we solved for the time, we know every variable except for the final angular velocity. Set it revolved 20 revolutions. That’s not the second or the third, it’s actually the fourth. I can’t have revolutions for delta theta and radians for acceleration. I don’t want the second one. So this is what we wanna know. And in fact, you use these, the exact same way you used these regular kinematic formulas.

We could do the same thing for the rotational motion variables. We wanna know azory. You just take the distance from the axis, to the point that you want to determine the speed and then you multiply it by the angular velocity and that gives you what the speed of that point is.

You too the square root. And we want the angular acceleration, that’s kinematya. We could find this area, relate it to omega and alpha and we’d get the wsory kinematic formulas, but we already know since these are all defined the same way the linear motion variables are defined, we’re gonna get the exact same equations, just with the linear motion variable replaced with its rotational motion variable.

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All right, this one we’re gonna have to actually use a kinematic formula for. So let’s right those down. Kinmatyka kinematyczne ruchu obrotowego. And we get the wxory of this point on the rod, four meters away from the axis is meters per second.

So we’ve got our angular displacement, what else do we know? Zero times t is still zero, so that’s all zero. So let’s do that. All right so these are the variables that are involved. It says how long, so that’s the time. Now there’s a couple ways we could solve this. So it’s gonna be 20 revolution times two pi radians per revolution.

We know the rest of these variables. So what do we do? That means that five revolutions would be five wsory two pi radians, which gives us 10 pi radians. It says it decelerates to a stop, which means it stops. So these are gonna travel, these points on the rod down here don’t travel very fast at all, because their r is so small. We wanna know the time. 